Point out the correct statement of the following about $\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}$
- Average oxidation number of $S$ atom is $+2$
- Oxidation number of two $S$ atoms is zero each and that of other two is $+5$ each
- Oxidation number of two $\mathrm{S}$ atoms is $+1$ each and that of other two is $+4$ each
- None of these
Solution

O.N. of two $S^{*}$ atoms are $+5$ each and that of other two S atoms is zero each. *
Asked in: JEE-TOPICTESTS-CHEMISTRY