$0.75 \mathrm{~g}$ platinic chloride of a mono- acidic base on ignition gives $0.245 \mathrm{~g}$ platinum.…
- $75.0$
- $93.5$
- 100
- $80.0$
Solution
$=\frac{\text { Acidity }}{2}\left(\frac{w t \text { of } \mathrm{Pt} \text { salt } \times 195}{\mathrm{wt} \text { of } \mathrm{Pt}}-410ight)$
$\therefore \mathrm{M} . \mathrm{wt}=\frac{1}{2}\left(\frac{0.75 \times 195}{0.245}-410ight)=93.5$
Asked in: JEE-TOPICTESTS-CHEMISTRY