Photons with energy of 5 eV are incident on a cathode, C in a photoelectric cell. The maximum energy of…

Photons with energy of 5 eV are incident on a cathode, C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C , no photoelectrons will reach the anode,  A , if, the stopping potential of A relative to C is
  1. +3 V
  2. +4 V
  3. -1 V
  4. -3 V

Solution

Emax=E-ϕ

2 eV=5 eV-ϕ⇒ϕ=3 eV.

Now, eV0=E-ϕ

=6 eV-3 eV=3 eV.

So, the stopping potential is -3 V.

Asked in: NEET 2016 (Phase 2)

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