Photons of wavelength $\lambda$ emitted by a source of power $P$ incident on a photo cell. If the current…
Photons of wavelength $\lambda$ emitted by a source of power $P$ incident on a photo cell. If the current produced in the cell is $I$, then the percentage of incident photons which produce current in the photo cell is. (where, $h$ is Planck's constant and $c$ is the speed of light in vacuum)
$\frac{100 e P c}{\ln \lambda}$
$\frac{100 e P \lambda}{I h c}$
$\frac{100 / h \lambda}{e P_C}$
$\frac{100 / h c}{e P \lambda}$
Solution
In photoemission, only one electron can produce one photon.
So, if only $x \%$ of incident photons can produce electrons, then
$
I=\frac{n}{t}=\frac{100 \times I \times h c}{e P \lambda}
$