Phosphorus reacts with \(\mathrm{SO}_2 \mathrm{Cl}_2\) to form \(\mathrm{PCl}_5\) and \(X\). At \(723…
Phosphorus reacts with \(\mathrm{SO}_2 \mathrm{Cl}_2\) to form \(\mathrm{PCl}_5\) and \(X\). At \(723 \mathrm{~K}, \mathrm{HCl}\) gas reacts with \(\mathrm{O}_2\) in the presence of \(\mathrm{CuCl}_2\) to form water and \(Y. Y\) reacts with \(X\) in water to form two acids \(A\) and \(B\). What are \(A\) and \(B\) respectively?
When thionyl chloride reacts with white phosphorus, phosphorus pentachloride and \(\mathrm{SO}_2\) is formed.
\(\mathrm{P}_4+10 \mathrm{SO}_2 \mathrm{Cl}_2 \longrightarrow 4 \mathrm{PCl}_5+10 \mathrm{SO}_2(X)\)
At \(723 \mathrm{~K}, \mathrm{HCl}\) gas reacts with \(\mathrm{O}_2\) in the presence of \(\mathrm{CuCl}_2\) to form water and \(\mathrm{Cl}_2(Y)\).
\(4 \mathrm{HCl}+\mathrm{O}_2 \xrightarrow[\mathrm{CuCl}_2]{\mathrm{723 \textrm {K }}} 2 \mathrm{Cl}_2+2 \mathrm{H}_2 \mathrm{O} \text { (Deacon process) }\)
\(\mathrm{Cl}_2(Y)\) react with \(\mathrm{SO}_2(X)\) in water to form two acids \(\mathrm{HCl}(A)\) and \(\mathrm{H}_2 \mathrm{SO}_4(B)\).
\(\underset{(X)}{\mathrm{SO}_2}+\underset{(Y)}{2 \mathrm{H}_2 \mathrm{O}}+\underset{(B)}{\mathrm{Cl}_2} \longrightarrow \underset{(A)}{2 \mathrm{HCl}}+\underset{\mathrm{H}_2}{\mathrm{SO}_4}\)