Phenol treated with chloroform in presence of sodium hydroxide, which further hydrolysed in presence of an…

Phenol treated with chloroform in presence of sodium hydroxide, which further hydrolysed in presence of an acid results
  1. Salicyclic acid
  2. Benzene-1,2-diol
  3. Benzene-1, 3-diol
  4. 2-Hydroxybenzaldehyde

Solution

Chloroform CHCl3 in the presence of an alkali NaOH undergoes formylation of phenol at the ortho-position. This is also called as the Reimer-Tiemann reaction.

Hence, the answer is option D.

Asked in: JEE Main 2024 (29 Jan Shift 2)

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