Phenol on treatment with C O 2 in the presence of NaOH followed by acidification produces compound X as the…
Solution
Two different reactions are taking place here Kolbe–Schmitt reaction and esterification reaction (treatment of the product of Kolbe–Schmitt reaction with
The two reactions can be written as follows:
1.Kolbe–Schmitt reaction: reaction of phenol with carbon dioxide in the presence of sodium hydroxide, followed by acidification converts phenol to 1−1− hydroxybenzoic acid (Salicylic acid).
2.Esterification reaction: The salicylic acid is then reacted with acetic anhydride to form aspirin.

Asked in: JEE Main 2018 (08 Apr)
Practice more Alcohols Phenols and Ethers questions on Aicharya



