Percentage of Se (at. mass \(=78.4)\) in peroxidase anhydrase enzyme is \(0.5 \%\) by weight, then minimum…
Percentage of Se (at. mass \(=78.4)\) in peroxidase anhydrase enzyme is \(0.5 \%\) by weight, then minimum molecular mass of peroxidase anhydrase enzyme is
\(1.576 \times 10^4\)
\(1.576 \times 10^3\)
15.76
\(2.136 \times 10^4\).
Solution
The enzyme must contain at least one atom of Se.
$\because \quad 0.5 \mathrm{~g}$ of Se is present in $100 \mathrm{~g}$ of enzyme
$\therefore \quad 78.4 \mathrm{~g}$ of Se will be present in $=\frac{100 \times 78.4}{0.5}$
$=1.576 \times 10^4 \mathrm{~g}$ of enzymes