Pent-1-ene reacts with diborane to form $\mathrm{X}$. X on oxidation using $\mathrm{H}_2 \mathrm{O}_2$ in…

Pent-1-ene reacts with diborane to form $\mathrm{X}$. X on oxidation using $\mathrm{H}_2 \mathrm{O}_2$ in the presence of aqueous $\mathrm{NaOH}$ gives $\mathrm{Y}$. Compound $\mathrm{Y}$ is
  1. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_3$
  2. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH}$
  3. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_2 \mathrm{CH}_3$
  4. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C}(\mathrm{OH})\left(\mathrm{CH}_3\right) \mathrm{CH}_3$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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