Paragraph: Tangents are drawn from the point $P(3,4)$ to the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$…
- $(3,0)$ and $(0,2)$
- $\left(-\frac{8}{5}, \frac{2 \sqrt{161}}{15}\right)$ and $\left(-\frac{9}{5}, \frac{8}{5}\right)$
- $\left(-\frac{8}{5}, \frac{2 \sqrt{161}}{15}\right)$ and $(0,2)$
- $(3,0)$ and $\left(-\frac{9}{5}, \frac{8}{5}\right)$
Solution

Asked in: JEE Advanced 2010 (Paper 2)