Paragraph: Let $p, q$ be integers and let $\alpha, \beta$ be the roots of the equation, $x^{2}-x-1=0$, where…

Paragraph: Let $p, q$ be integers and let $\alpha, \beta$ be the roots of the equation, $x^{2}-x-1=0$, where $\alpha \neq \beta$. For $n=0,1,2, \ldots$, let $a_{n}=p \alpha^{n}+q \beta^{n}$ FACT: If $a$ and $b$ are rational numbers and $a+b \sqrt{5}=0$, then $a=0=b$.
Question: If $a_{4}=28$, then $p+2 q=$
  1. 14
  2. 7
  3. 12
  4. 21

Solution

α 2 =α+1
α 4 = ( α 2 ) 2
α 4 = (α+1) 2
α 4 = α 2 +2α+1
α 4 =α+1+2α+1
α 4 =3α+2
 

Also   α+β=1

    a4=28   pα4+qβ4=p3α+2+q3β+2=28

   p3α+2+q3-3α+2=28

   α3p-3q+2p+5q=28     (as αQc) (as it is root of quadratic equation)

    p=q, 2p+5q=28   p=q=4

    p+2q=12

Asked in: JEE Advanced 2017 (Paper 2)

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