Paragraph: Let $a$, b and $c$ be three real numbers satisfying $\left[\begin{array}{lll}a & b &…

Paragraph: Let $a$, b and $c$ be three real numbers satisfying $\left[\begin{array}{lll}a & b & c\end{array}\right]\left[\begin{array}{lll}1 & 9 & 7 \\ 8 & 2 & 7 \\ 7 & 3 & 7\end{array}\right]=\left[\begin{array}{lll}0 & 0 & 0\end{array}\right]$ Question: If the point $P(a, b, c)$, with reference to (E), lies on the plane $2 x+y+z=1$, then the value of $7 a+b+c$ is
  1. 0
  2. 12
  3. 7
  4. 6

Solution

$ \begin{aligned} & \text { Given, }[a b c]_{1 \times 3}\left[\begin{array}{lll} 1 & 9 & 7 \\ 8 & 2 & 7 \\ 7 & 3 & 7 \end{array}\right]_{3 \times 3}=\left[\begin{array}{lll} 0 & 0 & 0 \end{array}\right] \\ & \Rightarrow \quad\left[\begin{array}{c} a+8 b+7 c \\ 9 a+2 b+3 c \\ 7 a+7 b+7 c \end{array}\right]=\left[\begin{array}{l} 0 \\ 0 \\ 0 \end{array}\right] \\ & \Rightarrow \quad a+8 b+7 c=0 \\ & \Rightarrow 9 a+2 b+3 c=0 \\ & \Rightarrow \quad a+b+c=0 \\ & \end{aligned} $ On multiplying Eq. (iii) by 2 , then subtract from Eq. (ii), we get $ 7 a+c=0 $ Again multiplying Eq. (iii) by 3 , then subtract from Eq. (ii), we get $ \begin{array}{ll} & 6 a-b=0 \\ \therefore \quad & b=6 a \text { and } c=-7 a \end{array} $ As $(a, b, c)$ lies on $2 x+y+z=1$ $ \begin{array}{lc} \Rightarrow & 2 a+b+c=1 \\ \Rightarrow & 2 a+6 a-7 a=1 \\ \Rightarrow & a=1, b=6 \text { and } c=-7 \\ \therefore & 7 a+b+c=7+6-7=6 \end{array} $

Asked in: JEE Advanced 2011 (Paper 1)

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