P scored 40 marks more than Q in an examination. If Q scored 10% less marks than P, then how much did Q score?

P scored 40 marks more than Q in an examination. If Q scored 10% less marks than P, then how much did Q score?
  1. 360
  2. 380
  3. 400
  4. 420

Solution

Let Q score q marks; then P scores $q + 40$. Q scored 10% less than P, so q = 90% of P: $q = 0.9(q + 40)$. This gives $10q = 9q + 360$, so $q = 360$. Q scored 360 marks.

Asked in: CSAT 2021

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