P b + d i l . HN O 3 → W a r m P + Q ↑ + H 2 O incorrect statement for Q is

1. Paramagnetic colourless gas
2. It is oxidized to paramagnetic coloured gas by air
3. It combines with $\mathrm{F}{\mathrm{e}}_2(\mathrm{S}{\mathrm{O}}_4{)}_3$
4. It is also obtained by disproportionation of $\mathrm{H}\mathrm{N}{\mathrm{O}}_2$

Solution

Here only statement in option C is incorrect as it combines with $\mathrm{F}\mathrm{e}\mathrm{S}{\mathrm{O}}_4$ and not it combines with $\mathrm{F}{\mathrm{e}}_2(\mathrm{S}{\mathrm{O}}_4{)}_3$
$\text{Pb}\text{+}\text{dil}{\text{. HNO}}_{\text{3}}\stackrel{\text{Warm}}{\to }{\text{Pb(NO}}_{\text{3}}{\text{)}}_{\text{2}}\text{+}\text{NO}\uparrow \text{+}{\text{H}}_{\text{2}}\text{O}$
 paramagnetic, coloured gas
$\mathrm{H}\mathrm{N}{\mathrm{O}}_2\to \mathrm{H}\mathrm{N}{\mathrm{O}}_3+\mathrm{N}\mathrm{O}\uparrow +{\mathrm{H}}_2\mathrm{O}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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