Oxidation state of manganese in potassium permanganate is:

Oxidation state of manganese in potassium permanganate is:
  1. $+3$
  2. $+7$
  3. $+5$
  4. $+1$

Solution

Oxidation number of $\mathrm{K}=+1$ Oxidation number of $\mathrm{O}=-2$ $\mathrm{KMnO}_4$ is a neutral molecule. $\therefore \quad$ Sum of the oxidation number of all atoms $=0$ Oxidation number of $\mathrm{K}+$ Oxidation number of $\mathrm{Mn}+4 \times($ Oxidation number of $\mathrm{O})=0$ $(+1)+($ Oxidation number of $\mathrm{Mn})+4 \times(-2)=0$ $1+($ Oxidation number of $\mathrm{Mn})=+8$ $\therefore \quad$ Oxidation number of $\mathrm{Mn}=+7$

Asked in: MHT CET 2023 (11 May Shift 1)

Practice more Redox Reactions questions on Aicharya