Oxidation state of iodine in $\mathrm{I}_3^{-}$is

Oxidation state of iodine in $\mathrm{I}_3^{-}$is
  1. $-(1 / 3)$
  2. +4
  3. +5
  4. -3

Solution

$\mathrm{I}_3^{-}$ $\downarrow$ $\mathrm{x}$ (let oxidation state of iodine) $3 x=-1$ $x=-1 / 3$

Asked in: MHT CET 2021 (21 Sep Shift 2)

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