Oxidation number of potassium in K 2 O , K 2 O 2 and K O 2 , respectively, is:

1. $+2,\mathrm{}+1$ and $+\frac{1}{2}$
2. $+1,\mathrm{}+1$ and $+1$
3. $+1,\mathrm{}+4$ and $+2$
4. $+1,\mathrm{}+2$ and $+4$

Solution

$K_{2}O\stackrel{+1}{K}-\stackrel{-2}{O}-\stackrel{+1}{K}$ oxygen is more E.N. than potassium

$K_2{O}_2\stackrel{+1}{K}-\stackrel{-1}{O}-\stackrel{-1}{O}-\stackrel{+1}{K}$

  $K{O}_2$

Asked in: JEE Main 2020 (07 Jan Shift 1)

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