Oxidation number of $\mathrm{S}$ involved in coordination bond in $\mathrm{Na}_{2} \mathrm{~S}_{2}…
Oxidation number of $\mathrm{S}$ involved in coordination bond in $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$ is
$-2$
$+2$
$+5$
$+6$
Solution
\(\mathrm{Na}^{+} \mathrm{O}^{-}-\underset{|| \atop \huge \stackrel{ }{\mathrm{O}}}{\stackrel{\huge \mathrm{S} \atop \uparrow}{\mathrm{S}}}-\mathrm{O}^{-} \mathrm{Na}^{+}\)
There is a coordinate bond between two sulphur atoms.
The oxidation number of acceptor \(\mathrm{S}\)-atom is -2.
Let, the oxidation number of other \(\mathrm{S}\)-atom be \(\mathrm{x}\).
\(\underset{\text { For } \mathrm{Na}}{2(+1)}+\underset{\text { For catoms }}{3 \times(-2)}+x+\underset{\text { For coordinate S-atoms }}{1(-2)}=0\)
\(x=+6\)
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