Oxidation number of \(\mathrm{Cr}\) in \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\) is

Oxidation number of \(\mathrm{Cr}\) in \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\) is
  1. +6
  2. -6
  3. +3
  4. 0

Solution

CO (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero). \(\left[\stackrel{0}{\mathrm{Cr}(\mathrm{CO})_6}\right] \text { : Hexacarbonyl chromium (0). }\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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