Osmotic pressure of one molar solution at $27^{\circ} \mathrm{C}$ is $(\mathrm{R}=0.082)$
Osmotic pressure of one molar solution at $27^{\circ} \mathrm{C}$ is $(\mathrm{R}=0.082)$
- $2 \cdot 46 \mathrm{~atm}$
- $12 \cdot 1$ atm
- $24 \cdot 6 \mathrm{~atm}$
- $1 \cdot 21$ atm
Solution
$\begin{aligned} \pi &=\operatorname{MRT}(M=\text { Molarity }) \\ &=1 \mathrm{~mol} \mathrm{dm}^{-3} \times 0.082 \mathrm{dm}^{3} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \times 300 \mathrm{~K}=24.6 \mathrm{~atm} \end{aligned}$
Asked in: MHT CET 2020 (14 Oct Shift 1)
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