Osmotic pressure of insulin solution at $298 \mathrm{~K}$ is found to be $0.0072 \mathrm{~atm}$. Hence,…
- $0.76 \mathrm{~cm}$
- $0.70 \mathrm{~cm}$
- $7.4 \mathrm{~cm}$
- $76 \mathrm{~cm}$
Solution
$=0.0072 \times 76 \mathrm{~cm}$ of $\mathrm{Hg}$
$=0.0072 \times 76 \times 13.6 \mathrm{~cm}$ of mercury column
$=h \times 1$ of water column
$h=0.0072 \times 76 \times 13.6 \mathrm{~cm}$
$=7.4 \mathrm{~cm}$ ,
Asked in: JEE-TOPICTESTS-CHEMISTRY