Optical path of a particular ray of light has travelled a distance of 3 cm in flint glass is same as that on…
Optical path of a particular ray of light has travelled a distance of 3 cm in flint glass is same as that on travelling a distance ' $x$ ' cm through another medium. The value of ' $x$ ' is [refractive index of flint glass $=1 \cdot 6$, refractive index of another medium $=1.25$ ]
3.84 cm
2.84 cm
1.84 cm
4.84 cm
Solution
As optical paths are equal,
$\begin{aligned}
& \mu_{\mathrm{g}} \mathrm{x}_{\mathrm{g}}=\mu_{\mathrm{m}} \mathrm{x}_{\mathrm{m}} \\
& \mathrm{x}_{\mathrm{m}}=\frac{\mu_{\mathrm{g}} \mathrm{x}_{\mathrm{g}}}{\mu_{\mathrm{m}}}=\frac{1.6 \times 3}{1.25}=3.84 \mathrm{~cm}
\end{aligned}$