Only $2 \mathrm{~mL}$ of $\mathrm{KMnO}_4$ solution of unknown molarity is required to reach the end point of a titration of $20 \mathrm{~mL}$ of oxalic acid $(2 \mathrm{M})$ in acidic medium. The molarity of $\mathrm{KMnO}_4$ solution should be $\qquad$ M.

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Aicharya · Accepted Answer

$\begin{aligned} & 	ext { eq. }\left(\mathrm{KMnO}_4ight)=	ext { eq. }\left(\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4ight) \ & \mathrm{M} 	imes 2 	imes 5=2 	imes 20 	imes 2 \ & \mathrm{M}=8 \mathrm{M}\end{aligned}$

Only \(2 \mathrm{~mL}\) of \(\mathrm{KMnO}_4\) solution of unknown molarity is required to reach the end…

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