One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy…
One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is
- 1:1000
- 1:1
- $1: 10$
- $1: 100$
Solution
$U_{1}=1000 \times 4 \pi r_{1}^{2} \times T$
$\frac{r_{2}}{r_{1}}=(1000)^{1 / 3}=10$
$U_{2}=4 \pi r_{2}^{2} T$
$\frac{U_{2}}{U_{1}}=\frac{4 \pi r_{2}^{2} T}{1000 \times 4 \pi r_{1}^{2} \times T}=\frac{100}{1000}=\frac{1}{10}$
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Asked in: MHT CET 2020 (14 Oct Shift 1)
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