One mole of oxygen gas at STP is equal to

One mole of oxygen gas at STP is equal to
  1. \(6.022 \times 10^{23}\) molecules of oxygen
  2. \(6.022 \times 10^{23}\) atoms of oxygen
  3. \(16 \mathrm{~g}\) of oxygen
  4. \(3.2 \mathrm{~g}\) of oxygen

Solution

I mole of \(\mathrm{O}_2(g)\) at STP contains Avogadro number \(\left(N_A=6.022 \times 10^{23} \mathrm{~mol}^{-1}\right)\) of \(\mathrm{O}_2\) molecules, which will occupy its molar volume, i.e, 22.4 L.

Asked in: AP EAMCET 2020 (17 Sep Shift 1)

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