One mole of $\mathrm{SO}_{3}$ was placed in a one litre reaction flask at a given temperature when the…
- $0.36$
- $0.675$
- $0.45$
- $0.54$
Solution

$\therefore 2 \alpha=0.6, \quad \therefore \alpha=0.3$
$\left[\mathrm{SO}_{3}ight]=1-2 \alpha=1-0.6=0.4$
$\left[\mathrm{SO}_{2}ight]=2 \alpha=0.6$
$\left[\mathrm{O}_{2}ight]=\alpha=0.3$
$\mathrm{~K}_{\mathrm{eq}}=\frac{\alpha \times(2 \alpha)^{2}}{(1-2 \alpha)^{2}}=\frac{0.3 \times 0.6 \times 0.6}{0.4 \times 0.4}=0.675$ /
Asked in: JEE-TOPICTESTS-CHEMISTRY