One mole of $A(g)$ is heated to $200^{\circ} \mathrm{C}$ in a one litre closed flask, till the following…
One mole of $A(g)$ is heated to $200^{\circ} \mathrm{C}$ in a one litre closed flask, till the following equilibrium is reached.
$A(g) ightleftharpoons B(g)$
The rate of forward reaction at equilibrium is $0.02 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$. What is the rate (in $\mathrm{mol} \mathrm{L}^{-1} \mathrm{~min}^{-1}$) of the backward reaction at equilibrium?
$0.04$
$0.01$
$0.02$
$1$
Solution
At equilibrium, rate of forward reaction $=$ rate of backward reaction
$\therefore$ rate of backward reaction at equilibrium $=0.02 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$
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