One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at…

One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, $27^{\circ} \mathrm{C}$. The work done on the gas will be:
  1. $300 R \ln 6$
  2. $300 \mathrm{R}$
  3. $300 \mathrm{R} \ln 7$
  4. $300 \mathrm{R} \ln 2$

Solution

Work done on gas $=\mathrm{nRT} \ell n\left(\frac{p_f}{p_1}\right)$ $ =\mathrm{R}(300) \ell \mathrm{n}(2)\left(\because \frac{P_f}{p_i}=2 \text { given }\right) $

Asked in: JEE Main 2018 (15 Apr Shift 1 Online)

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