One mole of an ideal gas expands adiabatically from an initial state ( T A ,   V 0 ) to final state ( T…

One mole of an ideal gas expands adiabatically from an initial state (TA, V0) to final state (Tf, 5V0). Another mole of the same gas expands isothermally from a different initial state (TB, V0) to the same final state (Tf, 5V0). The ratio of the specific heats at constant pressure and constant volume of this ideal gas is γ. What is the ratio TATB?

  1. 5γ-1
  2. 51-γ
  3. 5γ
  4. 51+γ

Solution

As we know for an Adiabatic process

TVγ-1=Constant.

⇒TAV0γ-1=Tf5V0γ-1            ...i

For Isothermal process

TB=Tf            ...ii

Dividing equation i by equation ii, we get

⇒TATB=5γ-1

Asked in: JEE Advanced 2023 (Paper 1)

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