One mole of an ideal gas expands adiabatically at constant pressure such that its temperature $\mathrm{T}…
One mole of an ideal gas expands adiabatically at constant pressure such that its temperature $\mathrm{T} \propto \frac{1}{\sqrt{\mathrm{V}}}$. The value of $\gamma$ for the gas is $\left(\gamma=\frac{C_p}{C_v}, V=\right.$ Volumeof thegas $)$
1.8
1.5
1.3
1.4
Solution
For an adiabatic process at constant pressure, we have
$\mathrm{TV}^{\gamma-1}=\text { constant }$
Given, $\mathrm{TV}^{1 / 2}=$ constant
Hence, $\gamma-1=\frac{1}{2} \quad$ or $\quad \gamma=1.5$
.