One mole of an ideal gas at $300 \mathrm{~K}$ is expanded isothermally from an initial volume of 1 litre to…

One mole of an ideal gas at $300 \mathrm{~K}$ is expanded isothermally from an initial volume of 1 litre to 10 litres. The $\Delta \mathrm{E}$ for this process is $(\mathrm{R}=2 \mathrm{cal}$ $\left.\mathrm{mol}^{-1} \mathrm{~K}^{-1}ight)$
  1. $163.7 \mathrm{cal}$
  2. zero
  3. $1381.1 \mathrm{cal}$
  4. 9 lit atm

Solution

For a finite change $\Delta \mathrm{E}=\mathrm{C}_{\mathrm{v}} \Delta \mathrm{T} .$ For an isothermal process $\Delta \mathrm{T}=0 .$ Hence $\Delta \mathrm{E}=0$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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