One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV - diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II.

Question

	LIST -I		LIST -II
A)	In process $I$	P)	Work done by the gas is zero
B)	In process $I I$	Q)	Temperature of the gas remains unchanged
C)	In process $I I I$	R)	No heat is exchanged between the gas and its surroundings
D)	In process $I V$	S)	Work done by the gas is $6 P_{0} V_{0}$

Aicharya · Accepted Answer

Process - I is an adiabatic process ∆ Q = ∆ U + W ∆ Q = 0 W = - ∆ U Volume of gas is decreasing ⇒ W < 0 ∆ U > 0 ⇒ Temperature of gas increases ⇒ No heat is exchanged between the gas and surrounding. Process - I I is an isobaric process (Pressure remain constant) W = P ∆ V = 3 P 0 3 V 0 - V 0 = 6 P 0 V 0 Process - I I I is an isochoric process (Volume remain constant) ∆ Q = ∆ U + W W = 0 ∆ Q = ∆ U Process - I V is an isothermal process (Temperature remains constant) ∆ Q = ∆ U + W ∆ U = 0 !

One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV -…

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