One Faraday of electricity liberates x × 10 – 1 gram atom of copper from copper sulphate, x is______.

Question

Aicharya · Accepted Answer

One Faraday of electricity means it is equivalent to one mole of electrons charge.

${Cu}^{2 +} + 2 e^{-} \to Cu$

$2$ Faraday $\to 1 mol Cu$

$1$ Faraday $\to 0.5 mol Cu$ deposit

$0.5 mol = 0.5 g atom = 5 \times 10^{- 1}$

$x = 5$

Solution