One end of a uniform metal rod of length $100 \mathrm{~cm}$ is placed in ice and the other end is placed in…

One end of a uniform metal rod of length $100 \mathrm{~cm}$ is placed in ice and the other end is placed in boiling water. A point of the rod which is at a distance of $60 \mathrm{~cm}$ from the ice end is maintained at a constant temperature of $325^{\circ} \mathrm{C}$. If $2 \mathrm{~g}$ of water is converted into steam per second, the mass of ice melted per second in steady state is (Latent heat of steam $=6.75$ times latent heat of fusion of ice)
  1. $13 \mathrm{~g}$
  2. $4 \mathrm{~g}$
  3. $6.75 \mathrm{~g}$
  4. $8 \mathrm{~g}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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