One die has two faces marked 1 , two faces marked 2 , one face marked 3 and one face marked 4 . Another die has one face marked 1 , two faces marked 2 , two faces marked 3 and one face marked 4. The probability of getting the sum of numbers to be 4 or 5 , when both the dice are thrown together, is

Question

Aicharya · Accepted Answer

$\mathrm{a}=$ number or dice 1
$\mathrm{b}=$ number on dice 2
$(a, b)=(1,3),(3,1),(2,2),(2,3),(3,2),(1,4),(4,1)$
Required probability
$\begin{aligned}
& =\frac{2}{6} \times \frac{2}{6}+\frac{1}{6} \times \frac{1}{6}+\frac{2}{6} \times \frac{2}{6}+\frac{2}{6} \times \frac{2}{6}+\frac{1}{6} \times \frac{2}{6}+\frac{2}{6} \times \frac{1}{6}+\frac{1}{6} \times \frac{2}{6} \\ & =\frac{18}{36}=\frac{1}{2}
\end{aligned}$ .

One die has two faces marked 1 , two faces marked 2 , one face marked 3 and one face marked 4 . Another die…

Solution