On reaction with sodium, $1 \mathrm{~mol}$ of a compound $\mathrm{X}$ gives $1 \mathrm{~mol}$ of…
- $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}$
- $\mathrm{CH}_{3} \mathrm{COOCH}_{2} \mathrm{CH}_{3}$
- $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$
- $\mathrm{CH}_{2}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$
Solution
$\mathrm{CH}_{2} \mathrm{OHCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}+2 \mathrm{Na} \longrightarrow \mathrm{NaOCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{ONa}+2 \mathrm{H}$ ,
Asked in: JEE-TOPICTESTS-CHEMISTRY
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