On moving a charge of 20 coulombs by $2 \mathrm{~cm}, 2 \mathrm{~J}$ of work is done, then the potential…
On moving a charge of 20 coulombs by $2 \mathrm{~cm}, 2 \mathrm{~J}$ of work is done, then the potential difference between the points is
0.1 V
8 V
2 V
0.5 V
Solution
$
\mathrm{W}=\mathrm{qV} \Rightarrow \mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=2 / 20=0.1 \mathrm{~V}
$
Here $W$ is the work done in moving charge $q$ from point $A$ to $B$