On mixing ethyl acetate with aqueous sodium chloride, the composition of the resultant solution is
- $\mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5+\mathrm{NaCl}$
- $\mathrm{CH}_3 \mathrm{Cl}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{COONa}$
- $\mathrm{CH}_3 \mathrm{COCl}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{NaOH}$
- $\mathrm{CH}_3 \mathrm{COONa}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$
Solution
Asked in: JEE Main 2004
Practice more Carboxylic Acid Derivatives questions on Aicharya