$\mathrm{XeF}_{6}$ on hydrolysis gives

$\mathrm{XeF}_{6}$ on hydrolysis gives
  1. $\mathrm{XeO}_{3}$
  2. $\mathrm{XeO}$
  3. $\mathrm{XeO}_{2}$
  4. $\mathrm{Xe}$

Solution

$$
\mathrm{XeF}_{6}+3 \mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{XeO}_{3}+6 \mathrm{HF}
$$ ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more P-BLOCK ELEMENTS GROUP 15 16 17 18 questions on Aicharya