On heating ozone, its volume
- Increases to \(1.5\) times
- Decreases to half
- Remain unchanged
- Becomes double
Solution
\(\begin{aligned}
& \mathrm{O}_3 \xrightarrow{\Delta} \mathrm{O}_2+\frac{1}{2} \mathrm{O}_2 \\
& \therefore 1 \text { mole } \mathrm{O}_3 \text { gas gives }=1+\frac{1}{2} \\
&=\frac{3}{2} \text { moles of } \mathrm{O}_2 .
\end{aligned}\)
\(\therefore\) Volume increases to \(3 / 2\) times
Asked in: JEE-TOPICTESTS-CHEMISTRY
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