On dividing $x^{2} + 5x + 6$ by $(x + 2)$, the remainder is

On dividing $x^{2} + 5x + 6$ by $(x + 2)$, the remainder is
  1. $0$
  2. $2$
  3. $-2$
  4. $6$

Solution

$p(-2) = 4 - 10 + 6 = 0$. Remainder $= 0$.

Asked in: MH-SSC-9

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