On adding KI to benzenediazonium chloride, the product obtained is
- benzene
- 1,4-diiodobenzene
- iodobenzene
- $1,3,5$-triiodobenzene
Solution
$\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{N}_{2}^{+} \mathrm{Cl}^{-}+\mathrm{KI} \stackrel{\Delta}{\longrightarrow} \mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{I}+\mathrm{N}_{2} \uparrow+\mathrm{KCl}$
Asked in: JEE-TOPICTESTS-CHEMISTRY