On a temperature scale ' X ', the boiling point of water is 65 ° X and the freezing point is - 15 ° X . Assuming that the X scale is linear. The equivalent temperature corresponding to - 95 ° X on the Fahrenheit scale would be

Question

On a temperature scale ' X ', the boiling point of water is 65 &#176; X and the freezing point is - 15 &#176; X . Assuming that the X scale is linear. The equivalent temperature corresponding to - 95 &#176; X on the Fahrenheit scale would be

Aicharya · Accepted Answer

The relation between two temperature scales can be written as follows

$\frac{65 - x}{65 - (- 15)} = \frac{212 - F}{180} . . . (1)$

Substitute the values of the known parameters in to equation (1) and sole to calculate the required temperature in Fahrenheit scale.

$\begin{array}{rcl} \frac{65 + 95}{80} & = & \frac{212 - F}{180} \\ \Rightarrow & 2 \times 180 = 212 - F \\ \Rightarrow & F = 212 - 360 \\ = & - 148 ° F \end{array}$

On a temperature scale ' X ', the boiling point of water is 65 ° X and the freezing point is -…

Solution

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Solution

On a temperature scale ' X ', the boiling point of water is 65 ° X and the freezing point is -…