On a graph, a school is shown $6$ units east and $2$ units north of a fixed origin. Taking east as positive…
On a graph, a school is shown $6$ units east and $2$ units north of a fixed origin. Taking east as positive $x$ and north as positive $y$, the coordinates of the school are:
$(2,6)$
$(6,2)$
$(-6,-2)$
$(-2,6)$
Solution
$x = 6$ (east) and $y = 2$ (north), so the school is at $(6,2)$.