$6 \mathrm{~g}$ of urea (molar mass $=60 \mathrm{~g} \mathrm{~mol}^{-1}$ ) and $9 \mathrm{~g}$ of glucose…

$6 \mathrm{~g}$ of urea (molar mass $=60 \mathrm{~g} \mathrm{~mol}^{-1}$ ) and $9 \mathrm{~g}$ of glucose $\left(\right.$ molar mass $\left.=180 \mathrm{~g} \mathrm{~mol}^{-1}\right)$ were dissolved in $35 \mathrm{~g}$ of water. The mass percent of urea and glucose is respectively
  1. 18,12
  2. 6,9
  3. 12,18
  4. 9,6

Solution

$\begin{aligned} & \text { } \mathrm{m} \% \text { of urea }=\frac{6 \mathrm{~g}}{(6+9+35) \mathrm{g}} \times 100=12 \% \\ & \mathrm{~m} \% \text { of glucose }=\frac{9 \mathrm{~g}}{50 \mathrm{~g}} \times 100=18 \%\end{aligned}$

Asked in: AP EAMCET 2023 (15 May Shift 2)

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