$\mathrm{E}_{\text {cell }}^0$ of the reaction $\mathrm{Mg}_{(\mathrm{s})}+2 \mathrm{Ag}^{+}(0.0001…

$\mathrm{E}_{\text {cell }}^0$ of the reaction $\mathrm{Mg}_{(\mathrm{s})}+2 \mathrm{Ag}^{+}(0.0001 \mathrm{M}) \rightleftharpoons \mathrm{Mg}^{2+}(0.01 \mathrm{M})+2 \mathrm{Ag}_{(\mathrm{s})}$ is $3.17 \mathrm{~V}$. The $\mathrm{E}_{\text {cell }}$ of the reaction and its cell notation respectively are :
  1. $2.993 \mathrm{~V}, \mathrm{Ag}\left|\mathrm{Ag}^{+}(0.0001 \mathrm{M}) \| \mathrm{Mg}^2+(0.01 \mathrm{M})\right| \mathrm{Mg}$
  2. $\text { 3.993 V, } \mathrm{Mg}\left|\mathrm{Mg}^{2+}(0.0001 \mathrm{M}) \| \mathrm{Ag}^{+}(0.01 \mathrm{M})\right| \mathrm{Ag}$
  3. $2.993 \mathrm{~V}, \mathrm{Mg}\left|\mathrm{Mg}^{2+}(0.01 \mathrm{M}) \| \mathrm{Ag}^{+}(0.0001 \mathrm{M})\right| \mathrm{Ag}$
  4. $\text { 3.993 V, Ag| } \mathrm{Ag}^{+}(0.01 \mathrm{M}) \| \mathrm{Mg}^{2+}(0.0001 \mathrm{M}) \mid \mathrm{Mg}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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