Of the following four aqueous solutions, the total number of those solutions whose freezing point is lower than that of $0.10 {MC}_{2} H_{5} OH$ is (Integer answer)
(i) $0.10 M {Ba}_{3} {({PO}_{4})}_{2}$
(ii) $0.10 M {Na}_{2} {SO}_{4}$
(iii) $0.10 M KCl$
(iv) $0.10 M {Li}_{3} {PO}_{4}$

Question

Of the following four aqueous solutions, the total number of those solutions whose freezing point is lower than that of

0.10 {MC}_{2} H_{5} OH

is (Integer answer)
(i)

0.10 M {Ba}_{3} {({PO}_{4})}_{2}

(ii)

0.10 M {Na}_{2} {SO}_{4}

(iii)

0.10 M KCl

(iv)

0.10 M {Li}_{3} {PO}_{4}

Aicharya · Accepted Answer

&#916;T f = ik f m As m is the same for all solutions so &#916;T f depends on Van't Hoff factor (i). Greater is i small is freezing point. &#160;Compound&#160; &#160;i&#160; C 2 H 5 OH 1 Ba 3 PO 4 2 5 Na 2 SO 4 3 KCl 2 Li 3 PO 4 4 So the given solutions have a lower freezing point than ethanol.

Of the following four aqueous solutions, the total number of those solutions whose freezing point is lower…

Solution