$2 \mathrm{~g}$ of oxygen contains number of atoms equal to that in

$2 \mathrm{~g}$ of oxygen contains number of atoms equal to that in
  1. $0.5 \mathrm{~g}$ of hydrogen
  2. $4 \mathrm{~g}$ of sulphur
  3. 7 g of nitrogen
  4. $2.3 \mathrm{~g}$ of sodium

Solution

O atoms in 2g of oxygen
$=\frac{2 \times \mathrm{N}_{\mathrm{A}}}{16}=0.125 \mathrm{~N}_{\mathrm{A} .} 4 \mathrm{~g}\left(=\frac{4}{32} \mathrm{~g}ight.$ -atom $)$ of sulphur also contains atom $=0.125 \mathrm{~N}_{\mathrm{A}}$ ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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