$20 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ on heating gave $8.8 \mathrm{~g}$ of $\mathrm{CO}_{2}$ and $11.2…

$20 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ on heating gave $8.8 \mathrm{~g}$ of $\mathrm{CO}_{2}$ and $11.2 \mathrm{~g}$ of $\mathrm{CaO}$. This is in accordance with
  1. The law of conservation of mass.
  2. The law of constant composition.
  3. The law of reciprocal proportion.
  4. None of these

Solution

$\mathrm{CaCO}_{3} ightarrow \mathrm{CaO}+\mathrm{CO}_{2}$
$\quad$ $\quad$ 20g $\quad$ 8.8g $\quad$ 11.2g
mass of reactant $=$ mass of products $=20 \mathrm{~g}$ Hence the law of conservation of mass is obeyed. ^

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