$2 \mathrm{~kg}$ of ice at $-20^{\circ} \mathrm{C}$ is mixed with $5 \mathrm{~kg}$ of water at $20^{\circ}…
- $7 \mathrm{~kg}$
- $6 \mathrm{~kg}$
- $4 \mathrm{~kg}$
- $2 \mathrm{~kg}$
Solution
Asked in: AP EAMCET 2017 (24 Apr Shift 1)
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